问个单纯PHP的问题判断匹配大于0的正整数正则怎么写

沦陷今生 发表于 2014-10-26 21:33:23

想写个函数
大于0的正整数返回参数本身
否则返回false

function gt0($int){
if(preg_match("/^\d*$/",$int))
{
return $int;
}
else{
return false;
}

}

echo gt0('-123')," \n";
echo gt0(-123)," \n";
echo gt0('123.321')," \n";
echo gt0(123.321)," \n";
echo gt0('-123.321')," \n";
echo gt0(-123.123)," \n";
echo gt0('w123')," \n";
echo gt0('123w')," \n";
echo gt0('12w3')," \n";
echo gt0('0')," \n";
echo gt0(0)," \n\n";

echo gt0('0123')," \n";
echo gt0(0123),"跪在了这里怎么回事啊？竟然输出83 \n";
echo gt0('01')," \n";
echo gt0(01)," \n";
echo gt0('')," \n";
echo gt0('1')," \n";
echo gt0('123')," \n";
echo gt0(1)," \n";
echo gt0(123)," \n";
echo gt0(10)," \n";
echo gt0(1023)," \n";

阿呆发表于 2014-10-27 09:46:48

echo 0123; //结果：83

Closer 发表于 2014-10-27 09:56:41

真是神奇，以前都沒注意過：
http://stackoverflow.com/questions/10461490/why-is-not-123-0123-in-java

一叶扁舟 发表于 2014-10-27 10:55:06

0开头是八进制，八进制0123换成十进制不就是83

xuyaokun 发表于 2014-11-1 14:49:10

楼主，if(preg_match("/^\d*$/",$int)) 你这写的对啊。

页: [1]

CodeIgniter 中国开发者社区's Archiver

问个单纯PHP的问题 判断匹配大于0的正整数正则怎么写

问个单纯PHP的问题判断匹配大于0的正整数正则怎么写